1.

A comerical sample of hydrogen peroxide is labelled as 10 volumeits percentage strength

Answer»

0.03
0.01
0.09
0.1

Solution :10 volume `H_(2)O_(2)` means 1L of `H_(2)O_(2)` GIVES 10 L `O_(2)` at STP according to equation
`2H_(2)O_(2)rarr2H_(2)O+O_(2)`
2mole `H_(2)O_(2)` give 1 MOL
`therefore` 10 L of `O_(2)` at STP is obtained from `H_(2)O_(2)`
`=(2)/(22.4)xx10 mol H_(2)O_(2)`
=0.89 mol `H_(2)O_(2)`
`therefore` 0.89 mol `H_(2)O_(2)` is present in 1L solution
Assuming DENSITY of solution as 1g `mL^(-1)` 1 L solution =1000g
Mass of `H_(2)O_(2)=0.89xx34=30.26 g`
percent strength of `H_(2)O_(2)`
`=("mass of" H_(2)O_(2)(g))/("mass of solution" (g))xx100`
`=(30.26)/(1000)xx100=3.026% `


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