1.

A comound with the molecular formula C_(4)H_(10)O_(3) is converted by the action of acetyl chloride into a compound with molecular mass 190. The original compound has

Answer»

no `- OH` GROUP
one `- OH` group
three `- OH` GROUPS
teo `- OH` groups

Solution :`RO-H+Cl-overset(O)overset(||)(C )-CH_(3)overset(-HCl)(rarr)R-O-overset(O)overset(||)(C )-CH-(3)`
During the reaction of COMPOUND containing an `OH` group (such as alcohol) with acetyl chloride, the hydrogen atom (of `OH` group) is replaced by an acetyl group `(CH_(3)CO-)`. this results in net increases in molecular MASS by `42` units.
`-H+CH_(3)-overset(O)overset(||)(C )-rarr(-1)+(43)rarr42`
Thus number of `OH` groups should be equal to the total increases in molecular mass divided by `42`. Molecular mass of compound before acetylation ltbRgt `=(12xx4+10xx1+16xx3)`
`=106`
Molecular mass of compound after acetylation=`190`
`:.` No. of `OH` groups`=(190-106)/(42)=(84)/(42)=2`


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