1.

A compass needle of magneticmoment60 Am^(2)pointing geopgraphical north at a place where the horizontal componentof earth fiedlis 40 mu Wbm^(-2)experiences a torque of 1.2 xx10^(-3) Nmthe declination of the place is

Answer»

`15^(@)`
`30^(@)`
`45^(@)`
`60^(@)`

Solution :`tau =MH sin theta`
`THEREFORE sin theta =(tau)/(MH)=1/2 therefore theta =30^(@)`


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