InterviewSolution
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InterviewSolution
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A compass needle placed at a distance r from a short magnet in tan A position showns a deflection of `60^(@)`. If the distance is increased to `r(3)^(1//3)`, then the deflection of the compass needle is:A. `30^(@)`B. `60^(@)xx(3)^(1//3)`C. `60^(@)xx(3)^(2//3)`D. `60^(@)xx(3)^(3//3)` |
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Answer» Correct Answer - A We know that for `tan A` position `mu_(0)/(4pi)(2M)/r^(3)=H tan theta` `:. Tan theta prop 1/r^(3)implies(tantheta_(2))/(tantheta_(1))=(r/(r(3)^(1/3)))^(3)=1/3` `:. tantheta_(2)=(tantheta_(1))/3=(tan 60^(@))/3=sqrt(3)/3=1/sqrt(3)` |
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