1.

A complex K_(x)[MnF_(6)] has magnetic moment 4.9BM what will be the oxidation state of Mn and value of x :

Answer»

`MN" "(II),x=4`
`Mn" "(III),x=3`
`Mn" "(IV),x=2`
`Mn" "(V),x=1`

Solution :`therefore mu=4.9" "B.M.,` so UNPAIRED electrons should be 4.
Mn (III) :
so, x=3


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