A compound [A] gives positive iodoform test in 5 minutes. When 6.0 g of [A] is treated with sodium metal, 1120 mL of hydrogen gas is evolved at NTP. It is assumed that [A] contains one atom of oxygen per molecule. Further when [A] reacts with PBr_(3), a compound [B] is formed which on reacting with benzene in the presence of anhydrous AlCl_(3) gives a compound [C]. the compound [C] is a well known industrial compound and is used in the commercial preparation of phenol. The molar mass of compound [A] is :

A compound [A] gives positive iodoform test in 5 minutes. When 6.0 g o

1.	A compound [A] gives positive iodoform test in 5 minutes. When 6.0 g of [A] is treated with sodium metal, 1120 mL of hydrogen gas is evolved at NTP. It is assumed that [A] contains one atom of oxygen per molecule. Further when [A] reacts with PBr_(3), a compound [B] is formed which on reacting with benzene in the presence of anhydrous AlCl_(3) gives a compound [C]. the compound [C] is a well known industrial compound and is used in the commercial preparation of phenol. The molar mass of compound [A] is :
Answer» `60.0" g mol"^(-1)` `90.0" g mol"^(-1)` `100.0" g mol"^(-1)` `120.0" g mol"^(-1)` SOLUTION :The data suggests that the compound [A] is an alcohol. `UNDERSET("2 moles")(2 ROH)+2Na rarr2RONa+underset(22400 mL)(H_(2))` 22400 mL of `H_(2)` is evolved from alcohol `=2` mol 1120 mL of `H_(2)` is evolved from alcohol `=1120/22400xx2=0.1` mol. Now, 0.1 mole of `ROH=` 6g `:.` 1.0 mole of `ROH =` 60 g