1.

A compound AB crystallized in bcc lattice with unit cell edge length of 480 pm. If the radius of B^(-) is 225pm, then the radius of A^(+) is

Answer»

225 PM
190.7pm
129.6pm
132.8pm

Solution :Body diagonal of a cube `= SQRT( 3) a `
`= 1.732 xx 480`
`=831.36 `pm
Body diagonal`= 2( r_(x^(+)) + r_(y^(-)))`
` r_(x^(+)) + r_(y^(-)) = ( 831.36)/( 2) = 415.68`pm
`:. r_(x^(+)) = 415.68 - 225`
`= 190.68 = 190.7 `pm


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