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A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96g. What are its emirical and molecular formulas? |
Answer» Solution :To calculate the empirical formula Hence, the empirical formula of the compound is `CH_(2)Cl` Step 2. CALCULATION of empirical formula mass E.F. mass of `CH_(2)Cl=12+2xx1+35.5=49.5` Step 3. Calculation of VALUE of n `n=("Molecular mass")/("E.F. mass")=(98.96)/(49.5)=2` Step 4. Calculation of molecular formula Molecular formula `=nxxE.F. = 2XX(CH_(2)Cl)=C_(2)H_(4)Cl_(2)` |
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