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A compound contains 4.07% hydrogen,24.27% carbon and 71.65% chlorine. Itsmolar mass is 98.96 g. What are itsempirical and molecular formulas? |
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Answer» hello I am not sure what happened Hydrogen Carbon Chlorine mass 4.07 24.27 71.65 RAM 1 12 35.5no. of moles 4.07/1 24.27/12 71.65/35.5 4.07 2.02 2.02divide by the 4.07/2.02 2.02/2.02 2.02least no 2 1 1 Empirical formula therefore is H2CCl the molecular formula is (EF)n=MF (1+1+12+35.5)=49.5......98.96/49.5=2 n=2 (H2CCl)2=H4C2Cl2 therefore the molecular formula is C2H4Cl2(dichloroethane) I don't know please like 👍 |
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