1.

A compound forms hcp structure, what is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Answer»

SOLUTION :Number of particles in the close PACKED structure = `0.5xx6.02xx10^(23)=3.01xx10^(23)`
Number of TETRAHEDRAL voids = ` 2xx3.01xx10^(23)=6.02xx10^(23)`
Number of ctahedral voids `= 3.01xx10^(23)`
`THEREFORE` total number of voids `=6.02xx10^(23)+3.01xx10^(23)=9.03xx10^(23)`


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