1.

A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it ? How many of these are tetrahedral voids ?

Answer»

Solution :NUMBER of ATOMS in 0.5 mol = `0.5 xx 6.022 xx 10^(23)= 3.011 xx 10^(23)`.
Number of octahedral voids = Number of atoms = `3.011 xx 10^(23)`
Number of tetrahedral voids =`2 xx "Number of atoms" = 2 xx 3.011 xx 10^(23)= 6.022 xx 10^(23)`.
It may be remembered that the number of octahedral voids is EQUAL to the number of atoms in close-packing while the number of tetrahedral voids is TWICE the number of atoms in close- packing.
Hence, total number of voids = `3.011 xx 10^(23) + 6.022 xx 10^(23) = 9.033 xx 10^(23)`


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