InterviewSolution
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InterviewSolution
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A compound H_(2)X with molar weight of 80 g is dissolved in a solvent having density of 0.4 g ml^(-1). Assumingno change in volume upon dissolution, the molality of a 3.2 molar solution is |
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Answer» `THEREFORE` moles of solute = 3.2 MOL CONSIDER 1 L Solution. `therefore` volume of SOLVENT = 1 L `P_("solvent")=0.4 g.mL^(-1) therefore m_("solvent")=P xx V=400 g` `therefore` molality `=(3.2 mol)/(0.4 kg)= 8` molal. |
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