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A compound has the molecular formula `X_(4)O_(6)`. If `10 g "of" X_(4)O_(6)` has `5.72 g X`, atomic mass of `X` is:A. `32 "amu"`B. `37 "amu"`C. `42 "amu"`D. `98 "amu"` |
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Answer» Correct Answer - A `(4a+96)gX_(4)O_(6) "has" 4ag X` `:. 10 g X_(4)O_(6)"has"[(4axx10)/(4a+96)]` `:. (4axx10)/(4a+96)=5.72 :. a=32` |
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