1.

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

Answer»

`C_4A_3`
`C_2A_3`
`C_3A_2`
`C_3A_4`

Solution :ANION A is in hcp ion.
The NUMBER of A ion in unit cell = 6
The number of octahedral VOIDS = 6
Cation C ion occupies 75% of space.
`THEREFORE`Number of `C = (6 xx 75)/(100) = 9/2`
`therefore ` Molecular formula = `C_(9/2)`
`therefore ` Molecular formula `= C_9A_12`
Molecular formula `= C_3A_4` (General ratio) .


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