Saved Bookmarks
| 1. |
A compound microscope has a eyepiece of focal length 10m and an objective of focal length 4cm. Calculate the magnification if an object is kept at a distanceof 5cm from the objective then final image is formed at the least distance of distinct vision. |
|
Answer» Solution :(c) We know `1/(v_(0))+1/5=1/4` `v_(0)=20cm` and magnification `(M)=(v_(0))/(u_(0))[1+D/(f_(e))]` `M=20/5[1+20/10]=12` |
|