1.

A compound microscope has a eyepiece of focal length 10m and an objective of focal length 4cm. Calculate the magnification if an object is kept at a distanceof 5cm from the objective then final image is formed at the least distance of distinct vision.

Answer»

`10`
`11`
`12`
`13`

Solution :(c) We know `1/(v_(0))+1/5=1/4`
`v_(0)=20cm`
and magnification `(M)=(v_(0))/(u_(0))[1+D/(f_(e))]`
`M=20/5[1+20/10]=12`


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