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A compound microscope has a magnification of 30. The focal length of its eyepiece is 5 cm. Assuming the final image to be formed at least distance of distinct vision, calculate the magnification produced by objective . |
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Answer» Solution :DATA supplied ,, = - 30.= 5 CMD= 25 cm,` "" m = m_(0) xx m_(E), "" m_(e) = (1 + (D)/(f_(e)))` `therefore m = m (1 + (D)/(f_(e)))` `- 30 = m_(0) ( 1 + (25)/(5) ) = m_(o) xx 6 ` |
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