1.

A compound microscope has a magnification of 30. The focal length of eye piece is 5 cm.Assuming the final image to be at least distance of distinct vision, find the magnification. produced by the objective.

Answer»

Solution :Magnification of compound MICROSCOPE, M = 30
Least DISTANCE of distinct vision, D = 25 CM
Now, M = `M_(o) xx M_(e)`
`=M_(o)xx[1+(D)/(f_(e))]`
`30=M_(o)xx[1+(25)/(5)]`
`M_(o) = (30)/(6) = 5`


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