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A compound microscope has a magnification of 30. The focal length of eye piece is 5 cm.Assuming the final image to be at least distance of distinct vision, find the magnification. produced by the objective. |
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Answer» Solution :Magnification of compound MICROSCOPE, M = 30 Least DISTANCE of distinct vision, D = 25 CM Now, M = `M_(o) xx M_(e)` `=M_(o)xx[1+(D)/(f_(e))]` `30=M_(o)xx[1+(25)/(5)]` `M_(o) = (30)/(6) = 5` |
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