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A compound of carbon, hydrogen and nitrogen contins these elements in the ratio 9:1:3.5. calcualte the empirical formula. If its molecular mass is 108, what is the molecular formula? |
Answer» Solution : The EMPIRICAL FORMULA `=C_(3)H_(4)N` Empirical formula mass `=(3xx12)+(4xx1)+14=54` `n=("Mol.mass")/("Emp.mass")=(108)/(54)=2` Thus, molecular formula of the compound `=2xx` Empirical formula `=2xxC_(3)H_(4)N` `=C_(6)H_(8)N_(2)`. |
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