1.

A compound of carbon, hydrogen and nitrogen contins these elements in the ratio 9:1:3.5. calcualte the empirical formula. If its molecular mass is 108, what is the molecular formula?

Answer»

Solution :
The EMPIRICAL FORMULA `=C_(3)H_(4)N`
Empirical formula mass `=(3xx12)+(4xx1)+14=54`
`n=("Mol.mass")/("Emp.mass")=(108)/(54)=2`
Thus, molecular formula of the compound
`=2xx` Empirical formula
`=2xxC_(3)H_(4)N`
`=C_(6)H_(8)N_(2)`.


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