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A compound of sodium does not give `CO_(2)` when heated but it gives `CO_(2)` when treated with dilute acids. A crystalline compound is found to have 37.1% Na and 14.52% `H_(2)O`. Hence, compound isA. `NaHCO_(3)*10H_(2)O`B. `NaHCO_(3)*5H_(2)O`C. `Na_(2)CO_(3)*10H_(2)O`D. `Na_(2)CO_(3)*H_(2)O` |
Answer» Correct Answer - D `CO_(2)` is obatined only when the compound is decomposed by acid thus, it is `Na_(2)CO_(3)`. It cannot be `NaHCO_(3)` since, it given `CO_(2)` on heating. Probable compound is `Na_(2)CO_(3).xH_(2)O` `{:(,,"Molar ratio","Ratio"),(Na_(2)CO_(3),85.48,0.8064,1),(H_(2)O,14.52,0.8064,1):}` Thus, compound is `Na_(2)CO_(3)*H_(2)O` Molecular weight `=124" g "mol^(-1)` percentage of sodium `=(2xx23)/(124)xx100=37.1%` |
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