A compound on anayalysis , was found to have the following composition. (i) Sodium=14.31%. (ii) Sulphur =9.97% (iii) Oxygen=69.50%, (iv) Hydrogen =6.22%. Calcualte the molecular formula of the compound assuming that whole of hydrogen in the compound is present as water of crystallisation Molecualr mass of the compound is 322.

A compound on anayalysis , was found to have the following composition

1.	A compound on anayalysis , was found to have the following composition. (i) Sodium=14.31%. (ii) Sulphur =9.97% (iii) Oxygen=69.50%, (iv) Hydrogen =6.22%. Calcualte the molecular formula of the compound assuming that whole of hydrogen in the compound is present as water of crystallisation Molecualr mass of the compound is 322.
Answer» Solution : The empirical formula`=Na_(2)SH_(20)O_(14)` Empirical formula MASS `=(2xx23)+32+(20xx1)+(14xx16)` =322 Molecular mass=`Na_(2)SH_(20)O_(14)` Whole of the hydrogen is present in the FORM of WATER. Thus, 10 water molecules are present in the molecule. So, molecular formula `=Na_(2)SO_(4).10H_(2)O`.