1.

A compound with mlecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. The number of amino group present per molecule of the former compound is

Answer»

6
2
5
4

Solution :In acetylation, one H-atom (at mass = 1 amu) of `NH_(2)` group is REPLACED by an acetyl group, i.e., `CH_(3)CO` (mol mass = 43 amu)
`-NH_(2)+CH_(3)COCl RARR NHCOCH_(3)+HCl`
It mean acetylation of each `NH_(2)` group increases the mass by 43-1=42 amu
Since the mol.mass of ORGANIC compound is 180 while that of the acetylated product is 390
`:.` increase in the mass DUE to acetylation `=390-180=210` amu
`:.` number of `NH_(2)=210//42 =5`


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