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A compound with molecular formula, C_(4)H_(10)O_(3) on acetylation with acetic anhydride gives a compound with molecular weight 190. find out the number of hydroxyl grouops present in the compound. |
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Answer» Solution :During acetylation, one H-atom (at. Mass=1amu) of the OH group is repalced by an acetyl group i.e., `CH_(3)CO` (mo mass=43amu). `-OH+(CH_(3)CO)_(2)Oto-O-COCH_(3)+CH_(3)COOH` in other WORDS, acetylation of each OH group increases the mass by 43-1=42 amu. now the mol. mass of `C_(4)H_(10)O_(3)=106` amu while that of the acetylated PRODUCT is 190 amu, therefore, the NUMBER of OH groups in the compound `=(190-106)/(42)=2` |
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