1.

A compound with molecular mass 180 is acylated with CH_(3)COCl to get a compound with molecular mass 390. the number of amio groups present per molecule of the former compound is

Answer»

6
2
5
4

Solution :During ACETYLATION, ONE H atom (at mass=1amu) of the `NH_(2)` group is REPLACED by an acetyl group, i.e.., `CH_(3)CO` (mol. Mass=43amu).
`-NH_(2)+CH_(3)COCl to -NHCOCH_(3)+HCl`
In other words, acetylation of each `NH_(2)` group increases the mass by 43-1=42 amu. now since the mol. mass of the organic COMPOUND is 180 while that of the acetylated product is 390, therefore, increase in the mass DUE to acetylation=390-180=210amu.
`therefore`No. of `-NH_(2)` groups`=(210)/(42)=5`


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