1.

A compound X_(2)O_(3) contains 31.58% oxygen by weight . The atomic mass of X is

Answer»

`34.66 " g mol"^(-1)`
`45.01 " g mol"^(-1)`
`52.00 " g mol"^(-1)`
`104.00 " g mol"^(-1)`

Solution :In compound `X_(2) O_(3)`
Percentageof OXYGEN by weight = 31.58
Percentageof X byweight = 68.42
LET theatomicmass ofX =x
`(2x)/(2x+48) xx 100=68.42`
Soatomicmass of XIS 52g `mol^(-1)`


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