1.

A compoundhas an empirical formula C_(2)H_(4)O. An independent analysisgave a value of 132.16 for its molecular mass.What is the correct molecular formula

Answer»

`C_(4)H_(4)O_(5)`
`C_(10)H_(12)`
`C_(7)O_(3)`
`C_(6)H_(12)O_(3)`

Solution :Empirical formula WIEGHT `C_(2)H_(4)O`
`= (12xx 2+ 4+16) = 44`
Molecular formula` = (" mol. Wt")/(" eq. formula wt.") XX " Emp. Formula"`
`= (132.1)/(44) xx" Empiriacal formula " = 3 xx C_(2)H_(4)O = C_(6)H_(12)O_(3)`.


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