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A concave lens of glass, refractive index 1.5, has both surface of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will have as a

Answer»

CONVERGENT LENS of focal length 3.5R.
convergent lens of focal length 3.0R.
divergent lens of focal length 3.5R.
divergent lens of focal length 3.0R.

Solution :Here `(1)/(f_(m))=((1.5)/(1.75)-1)((1)/((-R))-(1)/(R )))=-((25)/(1.75))(-(2)/(R ))=+(0.5)/(1.75R) rArr f_(m)=+3.5R`


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