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A concave mirror of focal length `20 cm` is cut into two parts from the middle and the two parts are moved perpendicularly by a distance `1 cm` from the previous principal axis `AB` .find the distance between the images formed by the two parts? A. 2 mmB. 6mmC. 3mmD. 4mm |
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Answer» Correct Answer - A For `M_(1): u=-10"cm"` f=-20 cm , `h_(0)= -0.1 "cm"` `v=(200)/(-10+20) = (200)/(10) implies v=20"cm"` `m=-(v)/(u) implies (h_(1))/(h_(0)) = (+20)/(+10)` `implies h_(1) = 2 xx -0.1 = -0.2 , h_(1) = -2` mm For `m_(2) = (-20)/(-10) = 2 implies h_(1) = 0.2 "cm" = 2"mm"` |
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