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A concave mirror of focal length 'fproduces a real image n times the sizeof the object. The distance of the objectfrom the mirror is(a) (n-1) f(c) (n+ 1) f/n (d) (n-1) f/rn |
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Answer» Option (a) Explanation:Focal Length = fMagnification = 1/n Now let object was placed at a distance. u = xNow, we know that m = |v/u| => v = x/n Applying Mirror Formula1/u + 1/v = 1/fPlug the values of u,v and f -1/x + n/x = 1/fn-1/x = 1/fx = ( n-1 )f |
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