1.

A condenser of capacity C_1 is charged to a potential V. The electrostatic energy stored in it is U_0 It is connected to another uncharged condenser of capacity C_2 in parallel. The energy dissipated in process is

Answer»

`((C_2 )/(C_1+C_2))U_0`
`((C_1)/( C_1 +C_2))U_0`
`((C_1 -C_2)/( C_1+C_2))U_0`
`((C_1 C_2)/(2(C_1 +C_2)))U_(0)^(2)`

ANSWER :A


Discussion

No Comment Found

Related InterviewSolutions