1.

A conductance cell has platinum electrodes, each with 5 cm^(2) area and separated by 0.5 cm distance. What is the cell constant?

Answer»

Solution :GIVEN :
Length = 0.5 cm
Area = 5 `cm^(2)`
Formula : CELL CONSTANT = `l/a`
Solution : Cell constant = `(0.5cm)/(5cm^(2))`
`""=0.1 cm^(-1)`
Cell constant = `0.1 cm^(-1)`.


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