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A conducting ring of radius 1 m is placed in a uniform magneticfield B of 0.01T oscillating with frequency 100Hz with its plane at right angle to B. What will be the induced electric field? |
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Answer» `piV//m` that is `e=-(Deltaphi)/(Deltat)` flux induced `=2BA cosphi` where `B` is magnetic field, `A` is area. Given, `theta=0^(@)=Deltat=(1)/(100)s` `Deltaf=2xx0.01xxpixx(1)^(2)xx200xcos 0^(@)` `:. e=(-2x0.01xxpixx(1)^(2)xx200)/(100)=-4pi` volt circumference of a CIRCLE of radius `r` is `2pir`. :. induced electric field `E` is `E=(|e|)/(2pir)=(4pi)/(2pir)=(2)/(1)=2V//m` |
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