1.

A conducting ring of radius r is placed perpendicular inside a time varying magnetic field as shown in figure. The magnetic field changes with time according to B = B_0 + alphat where B_0 and alpha are positive constants. Find the electric field on the circumference of the ring.

Answer»

`-PI alpha r^2`
`-pialphar`
`-pi alpha^2r^2`
`-pialpha^2r`

Solution :`phi=AB = pir^2 XX (B_0 + ALPHAT)`
`(dphi)/(dt)=pir^2 d/(dt)(B_0 +alphat)`
`THEREFORE (dphi)/(dt)=pir^2 (0+alpha)`
`therefore -epsilon=pir^2alpha`
`therefore epsilon=-pir^2alpha`


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