1.

A conducting rod of length l is higed at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field vec(B) in horizontal direction. The rod is released from the position shown in figure. Potential difference between the two ends of the rod is proportional to

Answer»

`L^(3//2)`
`l^(2)`
`sin theta`
`(sin theta)^(1//2)`

Solution :Potential difference `=(1)/(2)B omega l^(2)`
From energy conservation :
`MG.(1)/(2)sin theta =(1)/(2)I omega^(2)`, where `I=(ml^(2))/(3)`
`rArr omega prop (sin theta)^(1//2)rArr E prop omega rArr e prop (sin theta)^(1//2)`
Also `e prop l^(2)`.


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