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A conducting spherical bubble of radius r and thick-ness t(t lt lt r) is charged to a potential V. Now it collapses to form a spherical droplet. Find the potential of the droplet. |
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Answer» SOLUTION :Here charge and MASS are conserved. If R is the RADIUS of the resulting drop formed and `rho` is density of soap solution, `(4)/(3) piR^(3)rho=4pir^(2)t rho rArrR=(3r^(2)t)^(1//3)` Now potential of the bubble is `V=(1)/(4PI in_(0))(q)/(r )` or `q=4pi in_(0)rV` Now potential of resulting drop is `V^(1)=(1)/(4pi in_(0)) (q)/(R ) =((r )/(3t))^(1//3)V`. |
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