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A conducting square frame of side 'a' and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to : |
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Answer» `1/x^2` Inside (2) magnitude of induced emf is `epsilon_2=B_2 Vl` Induced emf value in frame `EPSILON=epsilon_1-epsilon_2` [Side (1) is NEAR to wire and `B PROP 1/r`] `THEREFORE epsilon=Vl (B_1-B_2)` `therefore epsilon prop (B_1-B_2)` but `B_1 prop 1/(x-a/2)` and `B_2 prop 1/(x+a/2)` `therefore epsilon prop (1/(x-a/2)-1/(x+a/2))` `therefore epsilon prop (2/(2x-a) -2/(2x+a))` `therefore epsilon prop (1/(2x-a)-1/(2x+a))` ( `because` 2 constant) |
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