1.

A conducting wire of length l and mass m can slide without friction on two parallel rails and is connected to capacitance C. The whole system lies in a magnetic field B and a constant force F is applied to the rod. Then

Answer»

the rod MOVES with constant VELOCITY
the rod moves with an acceleration of `(F)/(m+B^(2)l^(2)C)`
there is constant charge on the CAPACITOR.
charge on the capacitor increases with time

Solution :Current, `i=(dq)/(DT)=(d)/(dt)(CvBl)=CBL(dv)/(dt)=CBla`
`therefore F-CB^(2)l^(2)a=ma rArr a=(F)/(m+B^(2)l^(2)C)`
`rArr` emf increases `rArr` change increases


Discussion

No Comment Found

Related InterviewSolutions