A conducting wire of lengthand mass m is placed on a horizontal surface with its length along y direction. There exists a uniform magnetic field B along positive x direction. With wire carrying a current I in positive y direc- tion, the least value of force required to move it in x and y directions are F_(1) and F_(2). Now the direction of current in the wire is reversed and the value of two forces becomes F' _(1) and F'_( 2). Find the ratio of forces F_(1) : F_(2) : F'_(1) : F'_(2)

A conducting wire of lengthand mass m is placed on a horizontal surfac

1.	A conducting wire of lengthand mass m is placed on a horizontal surface with its length along y direction. There exists a uniform magnetic field B along positive x direction. With wire carrying a current I in positive y direc- tion, the least value of force required to move it in x and y directions are F_(1) and F_(2). Now the direction of current in the wire is reversed and the value of two forces becomes F' _(1) and F'_( 2). Find the ratio of forces F_(1) : F_(2) : F'_(1) : F'_(2)
Answer» ANSWER :`1:1:NE:ne` where `ne=(mg-Bil)/(mg+Bil)`

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