1.

A conductivity cell has been calibrated with a 0.01 M 1:1 electrolyte solution (specific conductance, k=1.25xx10^(-3)S" "cm^(-1)) in the cell and the measured resistance was 800 ohms at 25^(@)C. The constant will be

Answer»

1.02 cm
0.102 `cm^(-1)`
1.00 `cm^(-1)`
0.5 `cm^(-1)`

Solution :`K=1.25xx10^(-3)S" "cm^(-1):rho=(1)/(K)=(1)/(1.25xx10^(-3))`
`R=rho(l)/(A)`
`therefore800=(1)/(1.25xx10^(-3))XX((l)/(A))`, where `(l)/(A)=`cell CONSTANT
`(l)/(A)=800xx1.25xx10^(-3)=1`.


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