1.

A conductivity cell has been calibrited with 0.01 M electrolyte solution (k=1.25xx10^(-3)" S "cm^(-1)) in the cell and the measured resistance is 800 ohms at 25^(@)C. The cell constant will be :

Answer»

`1.02 CM^(-1)`
`0.102 cm^(-1)`
`1.00 cm^(-1)`
`0.5 cm^(-1)`

Solution :(c ) Specific CONDUCTANCE (k) `=(1)/(R )xx(1)/(a)`
`(L)/(a)=kxxR`
`=(1.25xx10^(-3)" OHM"^(-1)cm^(-1))xx(800" ohm")`
`=1.0 cm^(-1)`


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