1.

A conductivity cell having cell constant 8.76 cm^(-1) placed in 0.01 M solution of an electrolyte offered a resistance of 1000 ohms . What is the conductivity of the electrolyte ?

Answer»

`8.76 XX 10^(-4) ohm^(-1) cm^(-1)`
`8.76 xx 10^(-3) ohm^(-1) cm^(-1)`
`8.76 xx 10^(-2) ohm^(-1) cm^(-1)`
`8.76 xx 10^(-1) ohm^(-1) cm^(-1)`

Solution :`k = (1)/(R) xx` CELL const = `(1)/(1000) xx 8.76`
`= 8.76 xx 10^(-3) OMEGA^(-1) cm^(-1)`


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