1.

A conductivity cells has been calibrated with a 0.01 M 1:1 electrolyte solution (specific conductance,) K= (1.25 xx 10^(-3) S cm^(-1)) in the cell and the measured resistance was 800 ohms at 25^(@)C. The cell constant will be

Answer»

`1.02 cm^(-1)`
`0.102 cm^(-1)`
`1.00 cm^(-1)`
`0.5 cm^(-1)`

Solution :`K= 1.25 xx 10^(-3) S cm^(-1) : rho = 1/K = (1)/(1.25 xx 10^(-3))`
`R = rho (1)/(A), therefore 800= (1)/(1.25 xx 10^(-3)) xx (l/A)`,
Where `l/A =` Cell CONSTANT


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