1.

A conductivitycell filled with0.02 M AgNO_(3) gives at 25^(@) Cresistance of 947 ohms. If thecellconstant is 2.3 cm^(-1) . Whatis themolarconductivity of0.02M AgNO_(2)" at"25^(@)C

Answer»


Solution :Given :Concetration=C =0.02 M `AgNO_(2)`
Resistanceof solution= `R_("SOLN") = 947 Omega`
Cellconstant`= b =2.3 cm^(-1)`
MOLARCONDUCTIVITY= `^^_(m) = ?`
Conductivityof soln `= (" cellconstant ")/(R_("soln "))= ( b)/(R_("soln ")) = (23)/(947)`
`= 0.002429 Omega^(-1)cm^(-1)`
`"Molarconductivity" ^^_(m) = (KXX 1000)/( C) = (0.002429 xx 1000)/(0.02)`
`= 121. 5 Omega^(-1)cm^(2) mol^(-1)`


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