InterviewSolution
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InterviewSolution
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A conductor of length 3m moving in a uniform magnetic field of strength 100 T. It covers a distance of 70 m in 5 sec. Its plane of motion makes an angle of 30^(@) with direction of magnetic field. Calculate the emf induced in it. |
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Answer» Solution :`V= (x)/(t)= (70)/(5) =14ms ^(-1)` Component of velocity ALONG magnetic field `= V cos theta= V cos (90^(@) -30^(@))= V cos 60^(@)` `epsi =B L V cos theta ` `epsi =100 XX 3 xx 14 xx cos 60 ^(@)` `epsi =100 xx 3 xx 14 xx 1/2` ` epsi = 21000 V` |
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