1.

A conductor of length l is placed perpendicular to a horizontal uniform magnetic field B.Suddenly, a certain amount of charge is passed throgh it, when it is found to jump to a height h. The amount of charge that passes through the conductor is

Answer»

`(msqrt(gh))/(BL)`
`(msqrt(ht))/(2Bl)`
`(msqrt(2gh))/(Bl)`
none of these

Solution :Linera IMPULSE =mv
or `F/_\t=msqrt(2gh) or (ilB) /_\t=musqrt(2gh)`
But `i/_\t=/_\Q`
`:. (/_\q)(lB)=msqrt(2gh)`
`HENCE /_\q=(msqrt(2gh))/(BI)`


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