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A conductor of length l is placed perpendicular to a horizontal uniform magnetic field B.Suddenly, a certain amount of charge is passed throgh it, when it is found to jump to a height h. The amount of charge that passes through the conductor is |
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Answer» `(msqrt(gh))/(BL)` or `F/_\t=msqrt(2gh) or (ilB) /_\t=musqrt(2gh)` But `i/_\t=/_\Q` `:. (/_\q)(lB)=msqrt(2gh)` `HENCE /_\q=(msqrt(2gh))/(BI)` |
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