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A cone of radius 8 cm and height 12 cm is divided into two parts by a plane through the mid-point of its axis parallel to its base Find the ratio of the volumes of two parts |
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Answer» `AD=12/2=6 cm =h/2` `tantheta=r/h=(DE)/(h/2)` `DE=r/2` Volume of cone AEF=`1/3*pi(r/2)^2(h/2)` `=1/3pir^2h/8` Volume of cone=`1/3*pir^2h` Volume of `2^(nd)` part=`1/3pir^2h-1/3pir^2h/8` `=7/8pir^2h/3` `V_1/V_2=(1/3pir^2h/8)/(7/8pir^2h/3)=1/7`. |
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