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The radius of a spherical balloon increases from 7 cm to 14 cm as air is being pumped into it. Find the ratio of surface areas of the balloon in the two cases. |
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Answer» case 1`r= 7cm` TSA=`4 pi r^2` `=4 *22/7*7*7= 616cm^2` case 2`r=14cm` TSA=`4*22/7*14*14= 2464cm^2` ratio of surface areas= `(TSA^2)/(TSA_1)` `=2464/616` `=4:1` |
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