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A consider the situation in figure. The bottom of the pot is a reflecting plane mirror. F is a fish and B is a bird. (a) At what distance(s) from itself will the fish see the image (b) At what distance(s) from itself will the bird see theimage(s) of the fish? Take m_(wa) = 4/3 |
Answer» Solution :(a) For the FISH, the distance of bird from FREE surface is`(4h)/(3)`or 1.33 h, Distance of fish from the free surface = 0.5 h. So, the required distance is 1.83 h.  Again, effective distance of bird from themirror is nh + h or 2.33 h. So, distance of bird's image from mirror is 2.33 h. Distance from fish is 2.33 h +0.5 h i.e. 2.83 h. (b)For the bird, distance of fish from the freesurface is `(h)/(2n) " or " (h)/( 2 xx 4/3) " or "(3h)/(8) ` or 0.375 h Distance of fish from bird is 0.375 h + h i.e. 1.375 h. Again, distance of image of fish from mirror is ` h/2` Effective distance (for the bird) of the image of fish is the mirror is ` 1/n | (3h)/(2) | + h"i.e."3/4 xx (3h)/(2) + h " or " (9H)/(8) + h " or " (17h)/(8)` or 2.125 h . |
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