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A constant force `vecF=(3hati+2hatj+2hatk)` N acts on a particle displacing it from a position `vec(r_1)=(-hati+hatj-2hatk)m` to a new position `vecr_2=(hati-hatj+3hatk)m`. Find the work done by the force. |
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Answer» The displacement vectors, `vecs=vecr_2-vecr_1` `vecs=(1+1)hati+(-1-1)hatj+(3+2)hatk=2hati-2hatj+5hatk` From `W=vecF.vecs`, we have `W=(3hati+2hatj+2hatk)*(2hati-2hatj+5hatk)=6-4+10=12J` |
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