A constant torque of `200 Nm` turns a wheel of moment of inertia `50 kg m^(2)` about an axis through its centre. The angualr velocity `2` sec after staring form rest (in rad/sec) would be :

A constant torque of `200 Nm` turns a wheel of moment of inertia `50 k

1.	A constant torque of `200 Nm` turns a wheel of moment of inertia `50 kg m^(2)` about an axis through its centre. The angualr velocity `2` sec after staring form rest (in rad/sec) would be :
Answer» Correct Answer - `(8)` Here, `tau = 200 N.m, I = 50 kg m^(2)` `omega_(1) = 0, omega_(2) = ?, t = 2 s` `alpha = (tau)/(I) = (200)/(50) = 4 rad//sec^(2)` From `omega_(2) = omega_(1) + alpha t = 0 + 4 xx 2` `= 8 rad//sec`.

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A constant torque of `200 Nm` turns a wheel of moment of inertia `50 kg m^(2)` about an axis through its centre. The angualr velocity `2` sec after staring form rest (in rad/sec) would be :

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