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A constant voltage dc source is connected, as shown in Fig. A2.7, across two resistors of resistances 400 kOmega and 100 k Omega. What is the reading of the voltmeter, also of resistance 100 kOmega, when connected across the second resistor as shown? |
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Answer» 111 V across the DC supply is `450 KOMEGA`. CURRENT drawn from supply `1000 V//450 kOmega = 1//450A`. Potential DIFFERENCE across voltmeter is `(50 xx 1000)/450 V = (1000)/9 V = 111V` . |
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